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Tardigrade
Question
Mathematics
(1/2.5)+(1/5.8)+(1/8.11)+ ldots 16 terms =
Q.
2.5
1
+
5.8
1
+
8.11
1
+
…
16
terms
=
1386
185
AP EAMCET
AP EAMCET 2019
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A
25
4
B
25
8
C
25
16
D
25
1
Solution:
Given,
2
⋅
5
1
+
5
⋅
8
1
+
8
⋅
11
1
+
…
.16
terms
=
3
1
[
2
⋅
5
3
+
5
⋅
8
3
+
8
⋅
11
3
+
…
.
]
=
3
1
[
2
1
−
5
1
+
5
1
−
8
1
+
5
1
−
11
1
+
…
.
+
47
1
−
50
1
]
=
3
1
[
2
1
−
50
1
]
=
3
1
[
100
48
]
=
3
1
[
50
24
]
=
50
8
=
25
4