1.00 g of BaCl 2 is treated with excess of aqueous AgNO 3 and all chlorine is recovered as 1.38 g of AgCl. What is the atomic weight of Ba ? ( Cl =35.5, Ag =108)

Question

1.00 g of BaCl 2 is treated with excess of aqueous AgNO 3 and all chlorine is recovered as 1.38 g of AgCl. What is the atomic weight of Ba ? ( Cl =35.5, Ag =108) (A) 137 (B) 172.5 (C) 33 (D) 68.5

Tardigrade Admin · Accepted Answer

underset1 gBaCl2+2AgNO3 → underset1.38 g2AgCl+Ba(NO3)2 All chlorine atoms are recovered as AgCl hence number of moles of chlorine on both sides must be equal. Thus; 2 × number of moles of BaCl 2=1 × number of moles of AgCl 2 × (1/(x+35.5 × 2))=1 × (1.38/(108+35.5))⇒ x ≈ 137 (Say atomic mass of Ba =x )

Q. 1.00g of BaCl2​ is treated with excess of aqueous AgNO3​ and all chlorine is recovered as 1.38g of AgCl. What is the atomic weight of Ba ? (Cl=35.5,Ag=108)

137

172.5

33

68.5

Q. $1.00 g$ of $B a C l_{2}$ is treated with excess of aqueous $A g N O_{3}$ and all chlorine is recovered as $1.38 g$ of $A g Cl$ . What is the atomic weight of $B a$ ? $(Cl = 35.5, A g = 108)$