0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a a container of volume 10 m3 at 1000 K. given R is the gas constant in JK-1 mol-1 m, x is :

Question

0.5 moles of gas A and x moles of gas B exert a pressure of 200 Pa in a a container of volume 10 m3 at 1000 K. given R is the gas constant in JK-1 mol-1 m, x is : (A) (2 R/4 + 12) (B) (2 R/4 - R) (C) (4 - R/2 R) (D) (4 + R /2 R)

Tardigrade Admin · Accepted Answer

nT = (0.5 + x) PV = n × R × T 200 × 10 = (0.5 + x) × R × 1000 2 = (0.5 + x) R (2/R) = (1/2) + x (4/R) - 1 = 2x (4-R/2R) =x

Q. $0.5$ moles of gas $A$ and $x$ moles of gas $B$ exert a pressure of $200 P a$ in a a container of volume $10 m^{3}$ at $1000 K$ . given $R$ is the gas constant in $J K^{- 1} m o l^{- 1} m, x$ is :

$\frac{2 R}{4 + 12}$

$\frac{2 R}{4 - R}$

$\frac{4 - R}{2 R}$

$\frac{4 + R}{2 R}$

$n_{T} = (0.5 + x)$
$P V = n \times R \times T$
$200 \times 10 = (0.5 + x) \times R \times 1000$
$2 = (0.5 + x) R$
$\frac{2}{R} = \frac{1}{2} + x$
$\frac{4}{R} - 1 = 2 x$
$\frac{4 - R}{2 R} = x$

Q. 0.5 moles of gas A and x moles of gas B exert a pressure of 200Pa in a a container of volume 10m3 at 1000K. given R is the gas constant in JK−1mol−1m,x is :

4+122R​

4−R2R​

2R4−R​

2R4+R​