0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be

Question

0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be (A) pH2 > pSO2 > pCH4 (B) pH2 > pCH4 > pSO2 (C) pSO2> pH2 > pCH4 (D) pSO2 > pCH4 > pH2

Tardigrade Admin · Accepted Answer

Rate of diffusion propto (1/√ text molecular mass ) ∴ Order of diffusion: H 2> CH 4> SO 2 and amount left is in the order SO 2> CH 4> H 2 Hence, order of partial pressure is p SO 2>p CH 4> pH 2

Q. $0.5 m o l e$ of each of $H_{2}, S O_{2}$ and $C H_{4}$ are kept in a container. A hole was made in the container. After $3$ hours, the order of partial pressures in the container will be

$p H_{2} > pS O_{2} > pC H_{4}$

$p H_{2} > pC H_{4} > pS O_{2}$

$pS O_{2} > p H_{2} > pC H_{4}$

$pS O_{2} > pC H_{4} > p H_{2}$

Rate of diffusion $\propto \frac{1}{molecular mass}$
$∴$ Order of diffusion $: H_{2} > C H_{4} > S O_{2}$
and amount left is in the order $S O_{2} > C H_{4} > H_{2}$
Hence, order of partial pressure is $pS O_{2} > pC H_{4} > p H_{2}$

Q. 0.5mole of each of H2​,SO2​ and CH4​ are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be

pH2​>pSO2​>pCH4​

pH2​>pCH4​>pSO2​

pSO2​>pH2​>pCH4​

pSO2​>pCH4​>pH2​