Question

0.5 mol of potassium ferrocyanide contains carbon equal to

• A. 1.5 mol
• B. 36 g
• C. 18 g
• D. 3.6g

Answer 1

Answer: (B)

$K_4[Fe(CN{)}_6]$
$0.5$ has $C=\frac{1}{2}\times 6$ mol
$=3$ mol or $3\times 12=36g$