Question

$0.44g$ of a colourless oxide of nitrogen occupies $224ml$ at STP. The molecular formula is

• A. $NO$
• B. $N{O}_2$
• C. $N_{2}O$
• D. $N_2{O}_5$

Answer 1

Answer: (C)

Molecular weight $=\frac{\text{ Weight }}{\text{ Volume }}\times 22400ml$
$=\frac{0.44\times 22400}{224}=44$
Hence molecular formula $=N_{2}O$.