0.4 g of dihydrogen is made to react with 7.1 g of dichlorine to form hydrogen chloride. The volume of hydrogen formed at 273 K and 1 bar pressure is

Question

0.4 g of dihydrogen is made to react with 7.1 g of dichlorine to form hydrogen chloride. The volume of hydrogen formed at 273 K and 1 bar pressure is (A) 9.08L (B) 4.54L (C) 90.8L (D) 45.4L

Tardigrade Admin · Accepted Answer

The corresponding balanced reaction is:

H_{2} + C l_{2} \to 2 H Cl

Again,

0.4 g H_{2} = 0.4/2 m o l = 0.2 m o l

7.1 g C l_{2} = 7.1/71 m o l = 0.1 m o l

So,

C l_{2}

is the limiting reagent here.

Hence

0.2

moles of

H Cl

will be formed.

Again, we need to find out the volume of

H Cl

formed in the STP condition.

1 mol of gas in STP occupies

22.7 L

Thus,

0.2

mol of

H Cl

will occupy

= 4.54 L

Q. 0.4g of dihydrogen is made to react with 7.1g of dichlorine to form hydrogen chloride. The volume of hydrogen formed at 273K and 1 bar pressure is

9.08L

4.54L

90.8L

45.4L

Q. $0.4 g$ of dihydrogen is made to react with $7.1 g$ of dichlorine to form hydrogen chloride. The volume of hydrogen formed at $273 K$ and $1$ bar pressure is