0.24 g of a volatile gas, upon vaporisation, gives 45 mL vapour at NTP. What will be the vapour density of the substance ? (Density of H2 = 0.089)

Question

0.24 g of a volatile gas, upon vaporisation, gives 45 mL vapour at NTP. What will be the vapour density of the substance ? (Density of H2 = 0.089) (A) 95.93 (B) 59.93 (C) 95.39 (D) 5.993

Tardigrade Admin · Accepted Answer

Weight of gas =0.24 g Volume of gas ( V )=45 mL =0.045 L Density of H2(d)=0.089 Weight of 45 mL of H 2= V × d =0.045 × 0.089 =4.005 × 10-3 g Therefore, vapour density =( text Weight of certain volume of substance / text Weight of same volume of hydrogen ) =(0.24/4.005 × 10-3)=59.93

Q. 0.24g of a volatile gas, upon vaporisation, gives 45mL vapour at NTP. What will be the vapour density of the substance ? (Density of H2​=0.089)

95.93

59.93

95.39

5.993

Weight of gas =0.24g Volume of gas (V)=45mL=0.045L Density of H2​(d)=0.089 Weight of 45mL of H2​=V×d =0.045×0.089 =4.005×10−3g Therefore, vapour density = Weight of same volume of hydrogen Weight of certain volume of substance ​ =4.005×10−30.24​=59.93

Q. $0.24 g$ of a volatile gas, upon vaporisation, gives $45 m L$ vapour at NTP. What will be the vapour density of the substance ?
(Density of $H_{2} = 0.089$ )