0.2 mole sample of hydrocarbon CxHy yields after complete combustion with excess O2 gas, 0.8 mole of CO2, 1.1 mole of H2O Hence hydrocarbon is

Question

0.2 mole sample of hydrocarbon CxHy yields after complete combustion with excess O2 gas, 0.8 mole of CO2, 1.1 mole of H2O Hence hydrocarbon is (A) C4H10 (B) C4H8 (C) C4H5 (D) C8H16

Tardigrade Admin · Accepted Answer

CxHy+O2 arrow xCO2+(y/2) H2O beginmatrix0.2& 0&0.2x (y/2)×0.2 endmatrix given 0.2x = 8 beginmatrixx=4 0.1y =0.1 y=10 endmatrix ∴ C4H10

Q. $0.2$ mole sample of hydrocarbon $C_{x} H_{y}$ yields after complete combustion with excess $O_{2}$ gas, $0.8 m o l e$ of $C O_{2}$ , $1.1 m o l e$ of $H_{2} O$ Hence hydrocarbon is

$C_{4} H_{10}$

$C_{4} H_{8}$

$C_{4} H_{5}$

$C_{8} H_{16}$

$C_{x} H_{y} + O_{2} \to x C O_{2} + \frac{y}{2} H_{2} O$
$0.2 0 0.2 x \frac{y}{2} \times 0.2$
given $0.2 x = 8$
$x = 4 0.1 y = 0.1 y = 10$
$∴ C_{4} H_{10}$

Q. 0.2 mole sample of hydrocarbon Cx​Hy​ yields after complete combustion with excess O2​ gas, 0.8mole of CO2​, 1.1mole of H2​O Hence hydrocarbon is

C4​H10​

C4​H8​

C4​H5​

C8​H16​