Question

0.2 g sample of benzoic acid, $C_6{H}_{5}COOH$ is titrated with 0.12 M Ba ${\left(OH\right)}_2$ solution. What volume of $Ba(OH{)}_2$ solution is required to reach the equivalence point?

Molar mass of benzoic acid is 122 g $mo{l}^{-1}$ .

• A. 6.83 mL
• B. 13.6 mL
• C. 17.6 mL
• D. 35.2 mL

Answer 1

Answer: (A)

Number of moles of benzoic acid $=\frac{0.2}{122}=1.64\times 10^{-3}$

Neutralization takes place as $2C_6{H}_{5}COOH+Ba(OH{)}_2\to {\left(C_6{H}_{5}COO\right)}_{2}Ba+2H_{2}O$

Number of moles of $Ba(OH{)}_2$ required $=\frac{1}{2}\times 1.64\times 10^{-3}$

$\frac{MV}{l000}=\frac{1}{2}\times 1.64\times 10^{-3}$

$\frac{0.12\times V}{1000}=\frac{1}{2}\times 1.64\times 10^{-3}$

$V=6.83mL$