0.2 g of an organic compound contains C, H and O. On combustion, it yields 0.15 g CO2 and 0.12 g H2O. The percentage of C, H and O respectively is

Question

0.2 g of an organic compound contains C, H and O. On combustion, it yields 0.15 g CO2 and 0.12 g H2O. The percentage of C, H and O respectively is (A) C=15 %, H=20 %, O = 65 % (B) C = 10 %, H = 8.2 %, O = 81.8 % (C) C = 12.2 %, H=8.8 %, O = 79 % (D) C = 20 %, H = 6.66 %, O = 73.34 %

Tardigrade Admin · Accepted Answer

% of C=(12/44)×(0.15/0.2)×100=20 % % of H= (2/18)×(0.12/0.2)×100=6.66 % % of O=100-(20+6.66)=73.34 %

Q. $0.2 g$ of an organic compound contains $C, H$ and $O$ . On combustion, it yields $0.15 g$ $C O_{2}$ and $0.12 g H_{2} O$ . The percentage of $C, H$ and $O$ respectively is

$C = 15%, H = 20%, O = 65%$

$C = 10%, H = 8.2%, O = 81.8%$

$C = 12.2%, H = 8.8%, O = 79%$

$C = 20%, H = 6.66%, O = 73.34%$

$%$ of $C = \frac{12}{44} \times \frac{0.15}{0.2} \times 100 = 20%$
$%$ of $H = \frac{2}{18} \times \frac{0.12}{0.2} \times 100 = 6.66%$
$%$ of $O = 100 - (20 + 6.66) = 73.34%$

Q. 0.2g of an organic compound contains C,H and O. On combustion, it yields 0.15g CO2​ and 0.12gH2​O. The percentage of C,H and O respectively is

C=15%,H=20%,O=65%

C=10%,H=8.2%,O=81.8%

C=12.2%,H=8.8%,O=79%

C=20%,H=6.66%,O=73.34%