Question

$0.14$ gm of an acid required $12.5ml$ of $0.1NNaOH$ for complete neturalisation. The equivalent mass of the acid is:

• A. 63
• B. 56
• C. 45
• D. 112

Answer 1

Answer: (D)

$mEq$. of $NaOH=12.5\times 0.1$ $=1.25$
mEq. of acid $=$ mEq. of $NaOH$
Equivalent $=\frac{Wt}{Ew}$
$\therefore EW=\frac{Wt.}{\text{ Equivalent }}=\frac{0.14}{1.25\times 10^{-3}}$ $=112$