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Tardigrade
Question
Chemistry
0.1 M aqueous solution of K 4[ Fe ( CN )6] will have the same freezing point as 0.1 M aqueous solution of
Q.
0.1
M
aqueous solution of
K
4
[
F
e
(
CN
)
6
]
will have the same freezing point as
0.1
M
aqueous solution of
2211
165
Solutions
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A
F
e
(
S
O
4
)
3
B
A
l
2
(
S
O
4
)
3
C
A
lC
l
3
D
K
3
P
O
4
Solution:
0.1
M
K
4
[
F
e
(
CN
)
6
]
⟶
4
K
+
+
[
F
e
(
CN
)
6
]
−
4
Δ
T
f
=
i
(
K
f
×
m
)
i
=
5
(1)
0.1
M
F
e
(
S
O
4
)
3
⟶
F
e
2
+
+
3
S
O
4
2
−
(
i
=
4
)
(2)
A
l
2
(
S
O
4
)
3
⟶
2
A
l
3
+
+
3
S
O
4
2
−
(
i
=
5
)
(3)
A
lC
l
3
⟶
A
l
3
+
+
3
C
l
−
(
i
=
4
)
(4)
K
3
P
O
4
⟶
3
K
+
+
P
O
4
3
−
(
i
=
4
)
If
i
=
same
T
f
=
same
T
f
∝
i
for same concentration