0.02 gm equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a.gold solution, 1.314 g of gold is deposited. Find oxidation state of the gold. (Atomic mass of A u=197 ) (Write the nearest integer as your answer)

Question

0.02 gm equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a.gold solution, 1.314 g of gold is deposited. Find oxidation state of the gold. (Atomic mass of A u=197 ) (Write the nearest integer as your answer) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Ag ++ e - arrow Ag 1 mol (leq.) 0.02 q. of Ag =0.02 F =0.02 × 96500=1930 C 1.314 Au is deposited by 0.02 F 197 is deposited by (0.02/1.314) × 197=3 F

Q. $0.02 g m$ equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a.gold solution, $1.314 g$ of gold is deposited. Find oxidation state of the gold. (Atomic mass of $A u = 197$ )
(Write the nearest integer as your answer)

$A g^{+} + e^{-} \to A g$
$1$ mol (leq.)
$0.02 q$ . of $A g = 0.02 F = 0.02 \times 96500 = 1930 C$
$1.314 A u$ is deposited by $0.02 F$
$197$ is deposited by $\frac{0.02}{1.314} \times 197 = 3 F$

Q. 0.02gm equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a.gold solution, 1.314g of gold is deposited. Find oxidation state of the gold. (Atomic mass of Au=197 ) (Write the nearest integer as your answer)

Ag++e−→Ag 1 mol (leq.) 0.02q. of Ag=0.02F=0.02×96500=1930C 1.314Au is deposited by 0.02F 197 is deposited by 1.3140.02​×197=3F

Q. $0.02 g m$ equivalent of Ag was deposited in an electrolysis experiment. If same quantity of a electricity is passed through a.gold solution, $1.314 g$ of gold is deposited. Find oxidation state of the gold. (Atomic mass of $A u = 197$ )
(Write the nearest integer as your answer)

$A g^{+} + e^{-} \to A g$
$1$ mol (leq.)
$0.02 q$ . of $A g = 0.02 F = 0.02 \times 96500 = 1930 C$
$1.314 A u$ is deposited by $0.02 F$
$197$ is deposited by $\frac{0.02}{1.314} \times 197 = 3 F$