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Q.
Zn gives $H_2$ gas with $H_2SO_4$ and HCI but not with $HNO_3$ because :-
AIPMTAIPMT 2002The d-and f-Block Elements
Solution:
Zn have lower value of $E_{cell}^* $ and easily gives
oxidation. Zn is present above $H_2$ in
electrochemical series. So, it liberates hydrogen gas
from dilu. $HCI/H_2SO_4$. But $ HNO_3$ is an oxidising
agent. The hydrogen obtained in this reaction is
converted into $H_2O.$ In $HNO_3, \, NO_3^-$ ion is reduced
and give $NH_4 \, NO_3, \, N_2O, \, NO \, and \, NO_2$ (based upon
the concentration of $HNO_3$ )
[ $ Zn + 2HNO_3 \longrightarrow Zn \, ( NO_3)_2 + 2 H] \times 4 $
(Nearly 6% )
$ HNO_3 + BH \longrightarrow NH_3 + 3H_2O $
$ \frac{ NH_3 + HNO_2 \longrightarrow NH_4 \, NO_3}{ 4Zn + 10HNO_3 \longrightarrow 4 Zn ( NO_3)_2 + NH_4 \, NO_3 + 3H_2O} $