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Q. Y g of a non-volatile solute of molar mass M is dissolved in 250 g of benzene. If $K_{b}$ is molal elevation constant, the value of $\Delta\,T$ is given by:

Solutions

Solution:

$\Delta T=K_{b}\times\frac{w_{B}\times1000}{m_{B}\times w_{A}}$
$=K_{b} \times\frac{Y\times1000}{M\times250}$
$=\frac{4K_{b} Y}{M}$