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Chemistry
Y g of a non-volatile solute of molar mass M is dissolved in 250 g of benzene. If Kb is molal elevation constant, the value of Δ T is given by:
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Q. Y g of a non-volatile solute of molar mass M is dissolved in 250 g of benzene. If $K_{b}$ is molal elevation constant, the value of $\Delta\,T$ is given by:
Solutions
A
$2Y\,K_{b}/M$
9%
B
$4 Y \,K_{b}/M$
72%
C
$2Y\,K_{b}/4\,M$
7%
D
$2.5Y \,K_{b}/M$
13%
Solution:
$\Delta T=K_{b}\times\frac{w_{B}\times1000}{m_{B}\times w_{A}}$
$=K_{b} \times\frac{Y\times1000}{M\times250}$
$=\frac{4K_{b} Y}{M}$