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Q.
$XeO_{4}$ molecule is tetrahedral having ‘n’ number of $p\pi -d\pi $ bonds. The value of ‘n’ is
NTA AbhyasNTA Abhyas 2020Chemical Bonding and Molecular Structure
Solution:
Xenon undergoes $sp^{3}$ hybridization
In the fourth excited state xenon atom, has 8 unpaired electrons
One $\text{s}$ and three $\text{p}$ orbital undergo $\text{sp}^{\text{3}}$ hybridization. Four $sp^{3}$ hybrid orbitals form four σ bonds with oxygen atoms. They are $\text{σ} \, \text{sp}^{\text{3}} - \text{p}$ . Four pπ - dπ bonds are also formed with oxygen atoms by the unpaired electrons.
