Question

$XeF_{2}$ and $XeF_{6}$ are separately hydrolysed then

• A. both give out $O_{2}$
• B. $XeF_{6}$ gives $O_{2}$ and $XeF_{2}$ does not
• C. $XeF_{2}$ alone gives $O_{2}$
• D. Neither of them gives HF

Answer 1

Answer: (C)

On separate hydrolysis of $XeF_{2}$ and $XeF_{6}$ the products formed are as follows

$XeF_{2}+H_{2}O\overset{R . T .}{ \rightarrow }Xe+2HF+\frac{1}{2}O_{2}\uparrow$

$XeF_{6}+3H_{2}O\overset{R . T .}{ \rightarrow }XeO_{3}+6HF$