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  4. 'X’ grams of water is mixed in 69 grams of ethanol. Mole fraction of ethanol in the resultant solution is 0.6. What is the value of ‘X’ in grams

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Q. $'X’$ grams of water is mixed in $69$ grams of ethanol. Mole fraction of ethanol in the resultant solution is $0.6$. What is the value of $‘X’$ in grams

Solution:

$X_{A}=\frac{n_{A}}{n_{A}+n_{B}}$
$0.6=\frac{\frac{69}{46}}{\frac{69}{46}+\frac{x}{18}}$
$x = 18$