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Q. $X$ gram of $NH _{3}( g )$ will be required to add in $500ml,0.6NH_{2}SO_{4}$ to reduce the normality of $H_{2}SO_{4}$ to $0.1N$ . Calculate $4X$ value?

NTA AbhyasNTA Abhyas 2022

Solution:

M.eq. of $NH_{3}=500\times 0.6-500\times 0.1$
$=250M.eq$
$\frac{W}{E}\times 1000=250$
$\therefore W=\frac{250 \times 17}{1000}=4.25gm4X=4\times 4.25=17$