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  4. [X e O6]4 - is octahedral whereas XeF6 is a disordered one, because

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Q. $\left[X e O_{6}\right]^{4 -}$ is octahedral whereas $XeF_{6}$ is a disordered one, because

NTA AbhyasNTA Abhyas 2020The p-Block Elements - Part2

Solution:

Due to the presence of six fluoride ligands and one lone pair of electrons in $XeF_{6}$ , the structure lacks perfect octahedral symmetry and is disordered. In $\left[X e O_{6}\right]^{4 -}$ all the valence shell electrons of xenon are involved in the bonding with oxygen and hence, no lone pair of electrons is present. So, it has perfect octahedral geometry.