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Q. $X$ and $Y$ are two volatile liquids with molar weights of $10 \,g \,mol ^{-1}$ and $40\, g\, mol ^{-1}$ respectively. Two cotton plugs, one soaked in $X$ and the other soaked in $Y$, are simultaneously placed at the ends of a tube of length $L =24 cm$, as shown in the figure. The tube is filled with an inert gas at 1 atmosphere pressure and a temperature of $300\, K$. Vapours of $X$ and $Y$ react to form a product which is first observed at a distance $d cm$ from the plug soaked in $X$. Take $X$ and $Y$ to have equal molecular diameters and assume ideal behaviour for the inert gas and the two vapours.
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The value of $d$ in cm (shown in the figure), as estimated from Graham’s law, is

JEE AdvancedJEE Advanced 2014

Solution:

$\frac{ r _{ x }}{ I _{ Y }}=\frac{ d }{24- d }=\sqrt{\frac{40}{10}}=2$
$d =48-2 d$
$3 d =48$
$d =16\, cm$