Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. Write the value of current $i_{3}$ (in $mA$ ) in the circuit shown in the figure.
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$5\times 10^{3}I_{1}=60$
$\Rightarrow I_{1}=\frac{60}{5 \times 10^{3}}=12\,mA$
Potential difference across
$10\,k\Omega=240-60=180\,V$
So, $I_{3}\times 10\times 10^{3}=180$
$\Rightarrow I_{3}=18\,mA$
$I_{2}=I_{3}-I_{1}=6\,mA$