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Q.
Work done in the cyclic process shown in figure is
Thermodynamics
Solution:
Cyclic process is anticlockwise then
Work done $= -($ Area of $P-V$ graph$)$
$W=-\pi R_{1} R_{2}$
$=-\pi\left(\frac{3 P_{0}-P_{0}}{2}\right) \times\left(\frac{3 V_{0}-V_{0}}{2}\right)$
$=\frac{-22}{7} P_{0}\, V_{0}$