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Q.
With what minimum acceleration can a fireman slide down a rope whose breaking strength is two third of his weight?
Mechanical Properties of Solids
Solution:
Net downward force in the string, $ma=mg-T$
But $T_{min}$ $=\frac{2}{3}mg$ $\therefore $ $\quad$ $ma_{min}$ $=mg-\frac{2}{3}mg$
$a_{min}=g-\frac{2}{3}g=\frac{g}{3}$