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Q.
With what acceleration ‘a’ should the box of figure moving up so that the block of mass $M$ exerts a force $7\, Mg/4$ on the floor of the box?
Laws of Motion
Solution:
$FBD$ of $M$ : If $M$ exerts force $F = 7 Mg/4$ on floor, then from third law floor also exerts force $F$ on box in upward direction
$F -Mg = Ma$
$\Rightarrow \frac{7\,Mg}{4}-Mg=Ma$
$\Rightarrow a=\frac{3g}{4}$
