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Q. With a concave mirror, an object is placed at a distance $x_{1}$ from the principal focus, on the principal axis. The image is formed at a distance $x_{2}$ from the principal focus. The focal length of the mirror is

Ray Optics and Optical Instruments

Solution:

$\frac{1}{u}+\frac{1}{v}=\frac{1}{f}$
$\frac{1}{f-x_{1}}+\frac{1}{f-x_{2}}=\frac{1}{f} $
or $ \frac{f-x_{2}+f-x_{1}}{\left(f-x_{1}\right)\left(f-x_{2}\right)}=\frac{1}{f}$
or $f^{2}-f x_{2}-f x_{1}+x_{1} x_{2}=2 f^{2}-f\left(x_{1}+x_{2}\right)$
or $f^{2}=x_{1} x_{2}$ or $f=\sqrt{x_{1} x_{2}}$
This is Newton's mirror formula.