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Q. Why is $HCl$ not used to make the medium acidic in oxidation reactions of $KMnO_4$ in acidic medium?

The d-and f-Block Elements

Solution:

In case $HCl$ is used, it is oxidised to $Cl_2$.
$2KMnO_4 + 16HCl \rightarrow 2KCl + 2MnCl_2 + 8H_2O + 5Cl_2$