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Chemistry
Why does aqueous Fe ( III ) ion develop intense red colour when it reacts with SCN -ion while Fe ( II ) ion does not?
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Q. Why does aqueous $Fe ( III )$ ion develop intense red colour when it reacts with $SCN ^{-}$ion while $Fe ( II )$ ion does not?
The d-and f-Block Elements
A
Fe(III) ion forms a charge transfer complex with $SCN ^{-}$ions
B
$Fe ( III )$ is reduced to $Fe ( I )$ which is deep red in colour
C
$SCN ^{-}$ion is oxidized to $CN ^{-}$which forms red coloured complex with $Fe$ (III) ion
D
$SCN ^{-}$does not form any complex with $Fe$ (III) ion
Solution:
Correct answer is (a) Fe(III) ion forms a charge transfer complex with $SCN ^{-}$ions