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Q. White light is used to illuminate the two slits in a Young's
double slit experiment. The separation between the slits is b
and the screen is at a distance d (>> b) from the slits. At a
point on the screen directly in front of one of the slits, certain
wavelengths are missing. Some of these missing
wavelengths are

IIT JEEIIT JEE 1984

Solution:

At P (directly infront of $S_1$ ) y = b / 2
$\therefore $ Path difference,
$\Delta X=S_2 P-S_1 P=\frac{y.(b)}{d}=\frac{\big(\frac{b}{2}\big)(b)}{d}=\frac{b^2}{2d}$
Those wavelengths will be missing for which
$ \Delta X=\frac{\lambda_1}{2},\frac{3 \lambda_2}{2},\frac{5 \lambda_3}{2}...$
$\therefore \lambda_1=2 \Delta x=\frac{b^2}{d}$
$ \lambda_2=\frac{2 \Delta x}{3}=\frac{b^2}{3d}$
$ \lambda_3=\frac{2 \Delta x}{5}=\frac{b^2}{5d}$
$\therefore $ Correct options are (a) and (c).