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Q. While working on a physics project at school physics lab, you require a $4\, \mu F$ capacitor in a circuit across a potential difference of $1 \,kV$. Unfortunately, $4\, \mu F$ capacitors are out of stock in your lab but $2 \,\mu F$ capacitors which can withstand a potential difference of $400\, V$ are available in plenty. If you decide to use the $2\, \mu F$ capacitors in place of $4\, \mu F$ capacitor, minimum number of capacitors required are

Electrostatic Potential and Capacitance

Solution:

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$C_{A B}=\frac{2}{3}$
Total number of benches $=\frac{2 \,\not{4} \times 3}{\not{2}}=6$
Total number of capacitors $=6 \times 3=18$