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Q.
While launching a satellite of mass $10^{4} kg$, a force of $5 \times 10^{5} N$ is applied for $20\, s$. The velocity attained by the satellite at the end of $20\, s$, is
Laws of Motion
Solution:
Given, mass of satellite, $m=10^{4} kg$
$F=5 \times 10^{5} N , t=20\, s , u=0, v= ?$
Impulse applied on the satellite is equal to the change in momentum.
i.e. $F \cdot t=m(v-u)$
$5 \times 10^{5} \times 20=10^{4}(v-0)$
$\Rightarrow v=\frac{5 \times 10^{5} \times 20}{10^{4}}$
$=1000\, m / s =1\, km / s$