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Q. Which type of intermediate $(A)$ is formed during the reaction?
$CH_{3}CH_{2}-N=N-CH_{2}CH_{3} \xrightarrow{\text{Heat} } (A) +N_{2}$

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$CH_{3}CH_{2}-N=N-CH_{2}CH_{3} \xrightarrow{\text{Heat} } \underset{\text{Free radical (A)}}{{2CH_{3}\overset{·}{C} H_{2}+N_{2}}} $