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Q.
Which orbital gives an electron the greatest probability of being found close to the nucleus?
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Solution:
The orbital with lower value of $ (n+l) $ has lower energy and is close to the nucleus. Among $ 3s(3+0=3),3p(3+1=4) $ and $ 3d(3+2=5) $ orbitals, 3s has lower value of $ (n+l) $ , thus, it is close to the nucleus and provide a higher probability to the electron of being found close to the nucleus.