Question

Which one of the following statements is correct for the reaction?
$ CH _{3} COOC _{2} H _{5}(a q) + NaOH (a q) \longrightarrow $
$ CH _{3} COONa (a q)+ C _{2} H _{5} OH (a q) $

• A. Order is two but molecularity is one
• B. Order is one but molecularity is two
• C. Order is one but molecularity is one
• D. Order is two but molecularity is two

Answer 1

Answer: (D)

For the reaction,

$CH _{3} COOC _{2} H _{5}(a q) + NaOH (a q) \longrightarrow $

$CH _{3} COONa (a q)+ C _{2} H _{5} OH (a q)$

the molecularity is two because two molecules are taking part.

Moreover, rate law for the reaction is,

rate $(r)=k\left[ CH _{3} COOC _{2} H _{5}\right][ NaOH ]$

$\therefore $ Order of reaction is $1+1=2$