Number of oxygen atom in $2 g$ of $CO$ $=\frac{2}{28} \times 6.022 \times 10^{23} \times 1$
Number of oxygen atom in $2 g$ of $CO _2$ $=\frac{2}{44} \times 6.022 \times 10^{23} \times 2$
Number of oxygen atom in $2 g$ of $SO _2$ $=\frac{2}{64} \times 6.022 \times 10^{23} \times 2$
Number of oxygen atom in $2 g$ of $H _2 O$ $=\frac{2}{18} \times 6.022 \times 10^{23} \times 1$
Hence, $2 g$ of $H _2 O$ has maximum number of atoms of oxygen.