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Q. Which one of the following compounds will react with methyl magnesium iodide ?

MHT CETMHT CET 2008

Solution:

$CH_3 — CH_2— CH_2— C \equiv CH +\underset{\text{methyl magnesium bromide}}{CH_3MgBr}$

$\ce{->} CH_4 + Mg <^{Br}_{C \equiv CCH_2CH_2CH_3}$

due to the presence of acidic hydrogen

(hydrogen attached to triply bonded carbon atom) terminal alkyne (d) will react with

methyl magnesium bromide.