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Q.
Which one of the following compounds is a peroxide?
AIPMTAIPMT 2010The s-Block Elements
Solution:
In peroxide the oxidation number of $0$ is $-1$ and they give $H_2O_2$ with dilute acids and have peroxide linkage.
In $KO_2$ let O.S. of $O = x$
$\therefore $ $1 + (x \times 2) = 0 $
$\therefore = 1/2$ (It is a superoxide, not a peroxide).
In $BaO_2$, let $O.S.$ of $O = x$
$2 + (x \times 2) = 0$
$\therefore \, x = - 1 $(It is a peroxide)
In $MnO_2$ and $NO_2$, $Mn$ and $N$ exhibit variable oxidation states, the oxidation state of $0$ in these oxides is $-2$ and hence they are not peroxides. Among then only $BaO_2$ is a peroxide.