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Q. Which one of the following aqueous solutions will exhibit highest boiling point?

Jharkhand CECEJharkhand CECE 2008

Solution:

Boiling point $ ={{T}_{0}}(Solvent)+{{T}_{b}} $ (Elevation in b. p.)
$ \Delta {{T}_{b}}=mi{{k}_{b}} $
where, m is the molality ie, the van't Hoff factor (i)
$ =[1+(y-1)x] $ $ {{k}_{b}}= $
molal elevation constant.
Thus, $ \ \Delta {{T}_{b}}\propto im $
Assume 100% ionization [a]
$ mi(N{{a}_{2}}S{{O}_{4}})=0.01\times 3=0.03 $ [b]
$ mi(KN{{O}_{3}})=0.01\times 2=0.02 $ [c] $ mi(glucose)=0.015 $