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Q. Which one of the following alkenes when treated with $HCl$ yields majorly an anti Markovnikov product?

JEE MainJEE Main 2019Hydrocarbons

Solution:

In this case antimarkonikov product will be formed as major product because carbocation formed at a double bonded carbon having lesser number of H atom will be unstable due to presence of an electron withdrawing group $(CF_3)$ attached to it.

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