Question

Which of the products is formed when acetone is reacted with barium hydroxide solution?

• A. $ C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-C{{H}_{2}}-\underset{OH}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}} $
• B. $ C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}} $
• C. $ C{{H}_{3}}-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-\underset{OH}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-\underset{C{{H}_{3}}}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}} $
• D. $ C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-\underset{C{{H}_{3}}}{\overset{OH}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}} $

Answer 1

Answer: (A)

When treated with $ \text{Ba(OH}{{\text{)}}_{\text{2}}}\text{,} $ acetone undergoes aldol condensation to form diacetone alcohol.