Question

Which of the following will produce only one product on reduction with $LiAlH_{4}$ ?

• A. $\text{CH}_{3}\text{COOC}_{2}\text{H}_{5}$
• B. $\text{CH}_{3} \text{COOCH}_{2} \text{CH}_{2} \text{CH}_{\text{3}}$
• C. $\text{CH}_{3} \text{CH}_{2} \text{COOCH}_{2} \text{CH}_{3}$
• D. $\text{CH}_{3} \text{CH}_{2} \text{COOCH}_{3}$

Answer 1

Answer: (A)

$LiAlH_{4}$ in ether reduces ethyl acetate into ethyl alcohol.

$\text{CH}_{\text{3}} \text{COOC}_{\text{2}} \text{H}_{\text{5}} \text{+4[H]} \overset{\text{LiAlH}_{\text{4}}}{ \rightarrow } \text{2} \, \text{CH}_{\text{3}} \text{CH}_{\text{2}} \text{OH}$