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Q. Which of the following will have total number of $d-$ electrons equal to the difference in the number of total p and s electrons?

Classification of Elements and Periodicity in Properties

Solution:

The first inert gas which contains d electrons is in $4^{th}$ period i.e., Kr with atomic no. = 36

E.C. of $Kr =1 s ^{2} 2 s ^{2} 2 p ^{6} 3 s ^{2} 3 p ^{6} 4 s ^{2} 3 d ^{10} 4 p ^{6}$

Total number of d-electrons $=10$

Total number of p-electrons $=6+6+6=18$ Total number of s-electrons $=2+2+2+2=8$

Difference in $p$ and $s$ electron is $=18-8=10$