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  4. Which of the following will give silver mirror test?

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Q. Which of the following will give silver mirror test?

Rajasthan PETRajasthan PET 2001

Solution:

Aldehyde group $ (-CHO) $ reduces Tollen's reagent and gives silver mirror. Tollen's reagent is ammoniacal silver nitrate solution. Glucose contains $ -CHO $ group hence it gives silver mirror test. $ \underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} CHO \\ | \end{smallmatrix}}{\mathop{{{(CHOH)}_{4}}}}}\,+\underset{\begin{smallmatrix} Tollen's \\ reagent \end{smallmatrix}}{\mathop{A{{g}_{2}}O}}\,\xrightarrow[{}]{{}}\underset{\begin{smallmatrix} | \\ C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} COOH \\ | \end{smallmatrix}}{\mathop{{{(CHOH)}_{4}}}}}\,+\underset{\begin{smallmatrix} silver \\ mirror \end{smallmatrix}}{\mathop{2Ag\downarrow }}\, $