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Q. Which of the following transitions in $He ^{+}$ion will give rise to a spectral line which has the same wavelength as some spectral line in the hydrogen atom?
(1) $n=4$ to $n=2$
(2) $n=8$ to $n=4$
(3) $n=6$ to $n=3$
(4) $n=6$ to $n=2$

BHUBHU 2007

Solution:

Let the spectral line in the transition from $n=p$ to $n=q$ in hydrogen atom is same as the transition from $n=a$ to $n=b$ in helium atom.
Then $\left(\frac{1}{q^{2}}-\frac{1}{p^{2}}\right)=4\left(\frac{1}{b^{2}}-\frac{1}{a^{2}}\right)$
or $\frac{1}{q^{2}}-\frac{1}{p^{2}}=\left(\frac{2}{b}\right)^{2}-\left(\frac{2}{a}\right)^{2}$
This will be satisfied if $b=2 q$ and $a=2 p$ ie,
$a $ and $b$ should be even integers and greater than $1 .$