Energy radiated per second is given by
$ \frac{Q}{t}=P=A\varepsilon\sigma T^4 $
$ \Rightarrow \frac{P_1}{P_2}=\frac{A_1}{A_2}\left(\frac{T_1}{T_2}\right)^4=\left(\frac{r_1}{r_2}\right)^2.\left(\frac{T_1}{T_2}\right)^4 $
= $ \left(\frac{1}{4}\right)^2\left(\frac{4000}{200}\right)=\frac{1}{1} $
$ \therefore P_1 = P_2, $ hence option (d) is wrong.
Newton's law is an approximate from of Stefan's law of radiation and works well for natural convection.