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Q.
Which of the following statements is correct for $[Mn(CN)_{6}]^{3-}$ according to valence bond theory?
Coordination Compounds
Solution:
In $[Mn(CN)_{6}]^{3-}$, oxidation state of $Mn = +3, Mn^{3+} = 3d^{4}$
$[Mn(CN)_{6}]^{3-}$ :
It has two unpaired electrons.
$\mu=\sqrt{n\left(n+2\right)}=\sqrt{2\left(2+2\right)}=\sqrt{8}$
$=2.87 \, B.M.$