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Q.
Which of the following statements is correct for a reversible process in a state of equilibrium?
AIPMTAIPMT 2015Equilibrium
Solution:
The relationship between the Gibbs free energy change $\Delta G$, the standard Gibbs free energy change $\Delta G ^{\circ}$ and the equilibrium constant $K$ is
$\Delta G =\Delta G ^{ o }+2.303 RT \log K$
For a reversible process in a state of equilibrium $\Delta G =0$
Hence, $0=\Delta G ^{0}+2.303 RT \log K$
$\Delta G ^{ o }=-2.303 RT \log K$