Question

Which of the following species has the same hybridization as $C$ in $CH_{2}=CH_{2}$ ?

• A. $CO_{3}^{2 -}$
• B. $XeF_{4}$
• C. $PCl_{3}$
• D. $I_{3}^{-}$

Answer 1

Answer: (A)

Hybridization is the intermixing of the atomic orbitals that have similar or comparable energies.

Hybridisation can be calculated by the electron pair number method.

$ElectronPairHybridization2sp3sp^{2}4sp^{3}5sp^{3}d6sp^{3}d^{2}7sp^{3}d^{3}$

Electron pair can be calculated as the given below.

$E.P=\frac{valence electron of central atom + monovalent atom + negative charge - positve charge}{2}$

For $CO_{3}^{2 -}$

$E.P=\frac{4 + 0 + 2 + 0}{2}=3=sp^{2}$

For $XeF_{4}$

$E.P=\frac{8 + 4 + 2 + 0}{2}=6=sp^{3}d^{2}$

For $PCl_{3}$

$E.P=\frac{5 + 3 + 2 + 0}{2}=4=sp^{3}$

For $I_{3}^{-}$

$E.P=\frac{7 + 2 + 1 + 0}{2}=5=sp^{3}d$

Therefore the same hybridization as carbon in the above ethene molecule is only with the carbonate ion.