The sets of the quantum numbers and the corresponding orbitals are as shown below.
a) $n =3,1=0$ means $3 s -$ orbital
b) $n =3,1=1$ means $3 p -$ orbital
c) $n=4,1=2$ means $4 d -$ orbital
d) $n=4,1=0$ means $4 s -$ orbital
Increasing order of energy among three orbitals is $3 s <3 p <4 s <4 d$
$\therefore 4 d$ has highest energy.
Hence, the set c of quantum numbers $(n=4,1=2, m=1, s=+1 / 2)$ represents the highest energy of an atom.